SOLUTION: Every now and then even a good diamond cutter has a problem and the diamond breaks. for one cutter, the rate of breaks is .1%.
If this cutter works on 75 stones, what is the proba
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-> SOLUTION: Every now and then even a good diamond cutter has a problem and the diamond breaks. for one cutter, the rate of breaks is .1%.
If this cutter works on 75 stones, what is the proba
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Question 994081: Every now and then even a good diamond cutter has a problem and the diamond breaks. for one cutter, the rate of breaks is .1%.
If this cutter works on 75 stones, what is the probability that he breaks 2 or more?
I got 0.997420452. Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! we use the binomial probability formula
Probability(P) = (nCk) * p^k * q^(n-k) where nCk is the combination of n items taken k at a time
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P(k > or = 2) = 1 - ( P ( k = 0 ) + P ( k = 1 ) )
p = .001, q = .999, n = 75
P ( k = 0 ) = 0.927708673390002
P ( k = 1 ) = 0.0696477983025527
P(k > or = 2) = 1 - (0.927708673390002 + 0.0696477983025527)
P(k > or = 2) = 0.002643528
