Question 994073: The television show NBC Sunday Night Football broadcast a game between the Colts and Patriots received a share of 22, meaning that among the TV sets in use, 22% were tuned to the game (based on Nielson data). An advertiser wants to obtain a second opinion by conducting its own survey, and a pilot survey begins with 20 households having TV sets in use at the time of that same NBC Sunday Night Football broadcast.
(+3)
a. Find the probability that none of the households are tuned to NBC Sunday Night Football (show with the table in excel and also do using the multiplication rule)?
(+3)
b. at least one is (show using the table using the direct method and the complement method)?
(+3)
c. exactly one household?
(+3)
d. find P(X≤3)=?
I got 0.006948520, 0.046145272, 0.039196760, 0.328910820.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! None of the households would be 0.78^20 and your answer is correct.
At least one is the above answer subtracted from 1 or 0.9930. I used the complement method. At least 1 means not 0.
Exactly 1 is 20(0.22)(0.78^19)=0.0392 as you got.
For 2: 190*(0.22^2)(0.78^18)=0.1050
For 3: 1140(0.22^3)(0.78^17)=0.1777
I get basically the answer you got.
|
|
|
