SOLUTION: A stadium has 53,000 seats. Seats sell for ​$25 in Section​ A, ​$20 in Section​ B, and ​$15 in Section C. The number of seats in Section A equals the

Algebra ->  Matrices-and-determiminant -> SOLUTION: A stadium has 53,000 seats. Seats sell for ​$25 in Section​ A, ​$20 in Section​ B, and ​$15 in Section C. The number of seats in Section A equals the       Log On


   

Question 994047: A stadium has 53,000 seats. Seats sell for ​$25 in Section​ A, ​$20 in Section​ B, and ​$15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in 1,134,500 from each​ sold-out event. How many seats does each section​ hold?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
A=x
B+C=x
2x=53,500
x=26,500 seats in section A, and that generates $662,500.
B+C=26,500
20B+15C=472,000, since the total from A and B/C must equal $1,134,500
-20B-20C= -530,000, multiplying the top equation by (-20)
-5C=-58,000
C=11,600 seats
Therefore B=14,900 seats
A generates 662,500
B generates 298,000
C generates 174,000
They add to 1134500