SOLUTION: If you give 2/3 of fish to a friend and 2/5 to another friend and you only have 30 left how much did you have in the beginning

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: If you give 2/3 of fish to a friend and 2/5 to another friend and you only have 30 left how much did you have in the beginning      Log On


   

Question 993971: If you give 2/3 of fish to a friend and 2/5 to another friend and you only have 30 left how much did you have in the beginning
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
x fish initially
YOUR DESCRIPTION IS WRONG!
%281-2%2F3-2%2F5%29%2Ax=30, and LCD is 3%2A5.
%2815%2F15-%282%2F3%29%285%2F5%29-%282%2F5%29%283%2F3%29%29x=30

%2815%2F15-10%2F15-6%2F15%29x=30

%28%2815-16%29%2F15%29x=30

%28-1%2F15%29x=30

x=30%28-15%29

x=-45 which makes no sense. Recheck your problem description carefully.

Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.
YOUR DESCRIPTION IS WRONG!

Because 2%2F3 + 2%2F5 = 10%2F15 + 6%2F15 = 16%2F15 is just greater than  1.

I suspect that the condition should be changed like this:

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If you give  2%2F3  of fish to a friend and  2%2F5  of the remaining part  to another friend and you only have  30  left then how much did you have in the beginning?
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But it is your responsibility to formulate the problem correctly.