Question 99394This question is from textbook beginning and intermediate algebra
: A coin collector has 1.70 in dimes and nickels. She has two more dimes than nickels. How many nickels does she have
This question is from textbook beginning and intermediate algebra
Answer by timmy1729(23)   (Show Source):
You can put this solution on YOUR website! Let x be the number of nickels. So .05x is the amount of money in nickels and 0.10(x+2) is the amount of money in dimes since there are two more dimes than nickels. Think "number of nickels + 2 = number of dimes. So, .10(x+2) + 0.05x = $1.70.
To make this a lot easier, let's multiply it all by 100 to get rid of the decimal, which we will replace later.
10(x+2) + 5x = 170 That's much better isn't it?
10x + 20 + 5x = 170 Use the distributive property.
15x + 20 = 170 Add your x's
15x = 150 Subtract the 20 from both sides, now divide
x = 10 So there are 10 nickels.
Now, back to the original form:
0.10(10 + 2) + 0.05(10) = 1.70
0.10(12) + 0.05(10) = 1.70
1.20 + .50 = 1.70.
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