SOLUTION: Please help me solve this algebra problem! Solve the inequality. Express your answer in interval form. x2 + 36 < 12x Thank you!!!

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Question 993894: Please help me solve this algebra problem!
Solve the inequality. Express your answer in interval form.
x2 + 36 < 12x
Thank you!!!

Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52812) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve the inequality. Express your answer in interval form.
x2 + 36 < 12x
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Inequality  x%5E2+%2B+36 < 12x  is equivalent to this one:

x%5E2+-12+x+%2B+36 < 0.

The left side is  %28x+-+6%29%5E2.

It is the square of a real number,  so it is always non-negative.

Your inequality has no solutions.



The plot of  x%5E2+-12+x+%2B+36


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2+%2B+36+%3C+12x+
x%5E2-12x+%2B+36+%3C+0+
x%5E2-12x+%2B+6%5E2+%3C+0+
%28x-6%29%5E2+%3C+0+
in this case NO solution exist; whatever you choose for x the result inside parentheses will be squared, so final result will ALWAYS be positive number, and NEVER negative