SOLUTION: 1 2, 3, 4, 5, 6 NUMBERS OF PERSONS .41, .30, .14, .11, .03, .01 RENT STABILIZED Q. What is the variance of the number of person living in each unit? rent stabili

Algebra ->  Probability-and-statistics -> SOLUTION: 1 2, 3, 4, 5, 6 NUMBERS OF PERSONS .41, .30, .14, .11, .03, .01 RENT STABILIZED Q. What is the variance of the number of person living in each unit? rent stabili      Log On


   



Question 993831: 1 2, 3, 4, 5, 6 NUMBERS OF PERSONS
.41, .30, .14, .11, .03, .01 RENT STABILIZED
Q. What is the variance of the number of person living in each unit?
rent stabilized?
So the way i tried was
(1^2)(0.41)+(2^2)(0.30)+(3^2)(0.14)+(4^2)(.11)+(5^2)(.03)+(6^2)(.01) =5.74
variance = E(x^2)-[E(x)]^2 = 5.74-(2.08)^2 = 1.1436 as my answer but it shows incorrect.
Can you please help me identify where i am wrong or is my answer put in different? Please help with answer. THanks

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

1 2, 3, 4, 5, 6 NUMBERS OF PERSONS
.41, .30, .14, .11, .03, .01 RENT STABILIZED
Q. What is the variance of the number of person living in each unit?
rent stabilized?
So the way i tried was
(1^2)(0.41)+(2^2)(0.30)+(3^2)(0.14)+(4^2)(.11)+(5^2)(.03)+(6^2)(.01) =5.74
variance = E(x^2)-[E(x)]^2 = 5.74-(2.08)^2 = 1.1436 as my answer but it shows incorrect.
Can you please help me identify where i am wrong or is my answer put in different? Please help with answer. THanks
I got variance as: highlight_green%281.4136%29, which is what you should have gotten, but you seem to have copied the wrong value. You see, 5.74+-+2.08%5E2+=+1.4136, not 1.1436 as you posted. I hope this helps!!