Question 993633: If sin A=3/5 then find (tan A+sec A)^2
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If sin A=3/5 then find (tan A+sec A)^2
-------
Since sin = y/r, y = 3 and r = 5
---
Then, x = sqrt[5^2-3^2] = sqrt(16) = 4
----
So, tan(A) = y/x = 3/4 and sec(A) = r/x = 5/4
---
Ans: (tan(A)+sec(A))^2 = (3/4+5/4)^2 = 2^2 = 4
--------------
Cheers,
Stan H.
-----------
|
|
|
