SOLUTION: four consicutive odd integers whose sum is 296

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Question 993605: four consicutive odd integers whose sum is 296
Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

If n is an integer, then n%2B1, n%2B3, n%2B5, and n%2B7 will be first four odd consecutive integers.
if their sum is 296, than we have
%28n%2B1%29%2B%28n%2B3%29%2B%28n%2B5%29%2B%28n%2B7%29=296
n%2B1%2Bn%2B3%2Bn%2B5%2Bn%2B7=296
4n%2B16=296
4n=296-16
4n=280
n=280%2F4
n=70
so, your numbers are:
n%2B1=71,
n%2B3=73,
n%2B5=75, and
n%2B7=77


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
four consicutive [sic] odd integers whose sum is 296
consecutive
--------------
296/4 = 74, the center
There are 2 below and 2 above 74
--> 71, 73, 75, & 77