SOLUTION: The length of a rectangle is 17 meters less than twice the width. The perimeter of the rectangle is 203 meters. Find the dimensions.

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 17 meters less than twice the width. The perimeter of the rectangle is 203 meters. Find the dimensions.      Log On


   



Question 993576: The length of a rectangle is 17 meters less than twice the width. The perimeter of the rectangle is 203 meters. Find the dimensions.
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Make the width = 'x'
Length = 2x - 17
Perimeter = 2 x Width + 2 x Length
203 = 2(x) + 2(2x - 17)
203 = 2x + 4x - 34
collect like terms.
2x + 4x = 203 + 34
6x = 237
x = 237/6
x = 39.5 meters
Width = 39.5 meters
Length = 62 meters
Hope this helps :-)