SOLUTION: a motorboat maintained a constant speed of 15 miles per hour relative to the water in going 10 miles upstream and then returning. The total time for the trip was 1.5 hours. use thi

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Question 993541: a motorboat maintained a constant speed of 15 miles per hour relative to the water in going 10 miles upstream and then returning. The total time for the trip was 1.5 hours. use this information to find the speed of the current.
Answer by ikleyn(52790) About Me  (Show Source):
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A motorboat maintained a constant speed of 15 miles per hour relative to the water in going 10 miles upstream and then returning. The total time for the trip was 1.5 hours. use this information to find the speed of the current.
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Let  v  be the unknown current speed of the river in miles per hour.
When the motorboat moves upstream,  its speed relative to the bank of the river is  15-v  miles per hour,  and the time spent moving upstream is  10%2F%2815-v%29  hours.
When the motorboat moves downstream,  its speed relative to the bank of the river is 15%2Bv  miles per hour,  and the time spent moving downstream is  10%2F%2815%2Bv%29  hours.
So,  the total time upstream and downstream is  10%2F%2815-v%29+%2B+10%2F%2815%2Bv%29,  and it is equal to  1.5  hours,  according to the problem's input.
This gives an equation  10%2F%2815-v%29 + 10%2F%2815%2Bv%29 = 1.5.
To simplify the equation,  multiply both sides by  %2815-v%29%2A%2815%2Bv%29  and collect like terms.  Step by step,  you get
10%2815%2Bv%29+%2B+10%2815-v%29+=+1.5%2A%2815-v%29%2815%2Bv%29,
300 = 1.5%2A%2815%5E2-v%5E2%29,
200 = 15%5E2-v%5E2     (after dividing both sides by 1.5),
v%5E2 = 225+-+200,
v%5E2 = 25,
v = 5.

Answer.  The speed of the current is  5  miles per hour.

For more similar problems see the lesson  Wind and Current problems solvable by quadratic equations  in this site.

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