Instead of doing your problem for you, I'll do one exactly
like yours that takes exactly the same steps. The problem
I will do is:
Find two integers whose product is 329 such that one of the
integers is nine less than eight times the other integer.
Let the integers be x and y
>>...whose product is 329...<<
So xy = 329
>>...one of the integers is nine less than eight times
the other integer...<<
So we set y equal to 8 times x with 9 subtracted
from it to make it nine less:
y = 8x - 9
So we have this system of equations:
Substitute (8x-9) for y in the first
Using the + sign:
Using the - sign:
. That's not an integer so we
disregard it.
Substitute x=7 in
y = 8x - 9
y = 8(7) - 9
y = 56 - 9
y = 47
So the integers are 7 and 47.
Checking:
>>...whose product is 329...<<
7*47 = 329
>>...one of the integers is nine less than eight times
the other integer...<<
8 times 7 is 56, and indeed 47 is 9 less than 56.
So it checks.
Now do yours EXACTLY STEP BY STEP like this one.
Edwin