SOLUTION: How do i solve. 2/3(k—9)= 4(k—19)

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: How do i solve. 2/3(k—9)= 4(k—19)      Log On


   

Question 993464: How do i solve. 2/3(k—9)= 4(k—19)
Answer by farohw(175) About Me  (Show Source):
You can put this solution on YOUR website!

Assuming this is %282%28k-9%29%29%2F3+=+4%28k-19%29

%282%28k-9%29%29%2F3+=+4%28k-19%29 --> %282%28k-9%29%29%2F3+=+4k+-+76

3%2A%282%28k-9%29%2F3%29+=+3%2A%284k+-+76%29 --> 2%28k-9%29+=+12k+-+228

2k+-+18+=+12k+-+228 --> 2k+-12k+=+18+-+228

-10k+=+-210

%28-10k%29%2F-10+=+%28-210%29%2F-10

k+=+21