SOLUTION: two consecutive integers whose sum is eleven less than three times the smaller integer.

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Question 993399: two consecutive integers whose sum is eleven less than three times the smaller integer.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
S=smaller integer; L=larger integer=S+1
.
S+L=3S-11
S+S+1=3S-11
2S+1=3S-11
12=S
L=S+1=12+1=13
ANSWER: The numbers are 12 and 13
.
CHECK:
S+L=3S-11
12+13=3(12)-11
25=36-11
25=25