SOLUTION: Three times the sum of the first and third of three consecutive odd integers is 55 more than the second integer. Find the integers

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Question 993233: Three times the sum of the first and third of three consecutive odd integers is 55 more than the second integer. Find the integers
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Three times the sum of the first and third of three consecutive odd integers is 55 more than the second integer. Find the integers
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1st:: 2x-1
2nd:: 2x+1
3rd:: 2x+3
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Equation:
3[2x-1+2x+3] = 2x+1 + 55
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Solve for "x" then find the 3 consecutive odd numbers.
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Cheers,
Stan H.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Three times the sum of the first and third of three consecutive odd integers is 55 more than the second integer. Find the integers
Let the 1st integer be F

Then others are: F + 2, and F + 4

According to the clues: 3(F + F + 4) = F + 2 + 55

3(2F + 4) = F + 57

Continue on to the solution for F, the first

Then add 2 to the first to get the second

Add 2 to the second or 4 to the first to determine vale of the third