SOLUTION: Please help me solve the exponential and logarithmic equation: (4^x)-3(4^-x)=8

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please help me solve the exponential and logarithmic equation: (4^x)-3(4^-x)=8      Log On


   



Question 993221: Please help me solve the exponential and logarithmic equation:
(4^x)-3(4^-x)=8

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve the exponential and logarithmic equation:
(4^x)-3(4^-x)=8
----------------
4^x - 3(1/4^x) = 8
----------
Multiply thru by 4^x to get::
(4^x)^2 - 3 = 8(4^x)
-----
(4^x)^2 - 8(4^x) - 3 = 0
------
Let 4^x = w
----
w^2 - 8w - 3 = 0
---
w = [8+-sqrt(64-4(-3)]/2
---
w = [8+-sqrt(76)]/2
-----
Find the positive value of w::
w = 8.36
----
Solve for "x"::
4^x = 8.36
x = log(8.36)/log(4) = 1.53
--------------
Cheers,
Stan H.
------------