SOLUTION: Can you please help me solve the following problem?
Find three consecutive even integers such
that their sum is six less than twice the
smallest
what I have come up with is no
Algebra ->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: Can you please help me solve the following problem?
Find three consecutive even integers such
that their sum is six less than twice the
smallest
what I have come up with is no
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Question 993127: Can you please help me solve the following problem?
Find three consecutive even integers such
that their sum is six less than twice the
smallest
what I have come up with is not working.
I have the smallest number =s and the
sum=x therefore
s+(s+2)+(s+4)=x and x-6=2s+6
But every number I plug in does not
equate
What am I doing wrong? Found 2 solutions by ikleyn, MathTherapy:Answer by ikleyn(52803) (Show Source):
You can put this solution on YOUR website! .
Find three consecutive even integers such that their sum is six less than twice the smallest.
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Let x be the smallest of these three consecutive even integers.
Then the two others are (x+2) and (x+4).
Their sum is x + (x+2) + (x+4) = 3x + 6.
According to the condition,
3x + 6 = 2x - 6.
Hence,
x = -12.
Answer. The smallest of these three consecutive even integers is -12.
You can put this solution on YOUR website! Can you please help me solve the following problem?
Find three consecutive even integers such
that their sum is six less than twice the
smallest
what I have come up with is not working.
I have the smallest number =s and the
sum=x therefore
s+(s+2)+(s+4)=x and x-6=2s+6
But every number I plug in does not
equate
What am I doing wrong?
The sum is 6 less than TWICE the smallest, so you should have:
s + s + 2 + s + 4 = 2s - 6
Based on the above, you should be able to find your error(s). Move on then and solve the above for s to get
the value of the smallest integer!
