SOLUTION: george is twice as old as mary. and mary is three years older than juan. if juan is j years old, then what, in terms of j will be georges age in 10 years. a) 2j-4 b)2j-14 C) 2j

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: george is twice as old as mary. and mary is three years older than juan. if juan is j years old, then what, in terms of j will be georges age in 10 years. a) 2j-4 b)2j-14 C) 2j      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 992943: george is twice as old as mary. and mary is three years older than juan. if juan is j years old, then what, in terms of j will be georges age in 10 years.
a) 2j-4
b)2j-14
C) 2j+13
d) 2j +16
e) 2j+26
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
j = juan's current age in years
m = marry's current age in years
g = george's current age in years

"mary is three years older than juan" means m+=+j%2B3

"george is twice as old as mary" so we know g+=+2m

Replace the 'm' in george's equation with 'j+3' to get g+=+2%28j%2B3%29+=+2j%2B6

So currently, george is 2j%2B6 years old.

Add 10 years to this expression to get 2j%2B6%2B10=2j%2B16

In 10 years, george will be 2j+16 years old, where j is juan's current age. So the answer is d) 2j +16