SOLUTION: Hello! Hope anyone can help me :) The topic is dividing radicals The area of a rectangular streamer is 20 sq.m its width is 2 sqrt(2) jow long is the streamer? Thank you in adva

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Question 992767: Hello! Hope anyone can help me :)
The topic is dividing radicals
The area of a rectangular streamer is 20 sq.m its width is 2 sqrt(2) jow long is the streamer?
Thank you in advance! :)
Found 3 solutions by Cromlix, stanbon, rothauserc:
Answer by Cromlix(4381)   (Show Source):
You can put this solution on YOUR website!
Hi there,
Area of rectangular streamer = 20 sq m
Width is 2 sqrt 2
Area of rectangle = width x length
20 = 2 sqrt 2 x length
Length = 20/2 sqrt 2
Length = 5 sqrt 2
..........
Proof:
2 sqrt 2 x 5 sqrt 2
sqrt 8 x sqrt 50
= sqrt 400
= 20.
Hope this helps :-)

Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
The area of a rectangular streamer is 20 sq.m its width is 2 sqrt(2) how long is the streamer?
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Area/width = length
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length = 20 m^2/(2sqrt(2)) = 10/sqrt(2) = 10sqrt(2)/2 = 5sqrt(2)m
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cheers,
Stan H.

Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website!
Area(A) of rectangle = length * width, then
20 = length * (2*sqrt(2))
length = 20 / (2*sqrt(2))
length = 10 / sqrt(2)
multiply the numerator and denominator by sqrt(2)
length = (10*sqrt(2)) / 2 = 5*sqrt(2)
length = 5*sqrt(2) meters