SOLUTION: Find the point with coordinates of the form (3a, a) that is in the third quadrant and is a distance 5 from P(1, 2). (x, y) =

Algebra ->  Coordinate-system -> SOLUTION: Find the point with coordinates of the form (3a, a) that is in the third quadrant and is a distance 5 from P(1, 2). (x, y) =       Log On


   

Question 992593: Find the point with coordinates of the form (3a, a) that is in the third quadrant and is a distance 5 from
P(1, 2).
(x, y) =



Answer by anand429(138) About Me  (Show Source):
You can put this solution on YOUR website!
%283a-1%29%5E2+%2B+%28a-2%29%5E2+=+5%5E2
=> +9a%5E2-6a%2B1%2Ba%5E2-4a%2B4=25
=> +10a%5E2-10a-20=0
=> a%5E2-a-1+=0
Solve for a, and choose only negative value(a is approx -0.618), since the pt. is in 3rd quadrant.