SOLUTION: Mary has $6.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and ninety-eight more nickels than dimes, how many coins of each type does she have?
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: Mary has $6.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and ninety-eight more nickels than dimes, how many coins of each type does she have?
Log On
Question 992369: Mary has $6.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and ninety-eight more nickels than dimes, how many coins of each type does she have? Answer by solver91311(24713) (Show Source):
Let represent the number of quarters. Then is the number of dimes and is the number of nickels. Nickels are worth 5 cents, dimes are worth 10 cents, and quarters are worth 25 cents. The total value of the coins is $6.00 which is equivalent to 600 cents. Hence:
Solve for , then calculate , and
John
My calculator said it, I believe it, that settles it
