SOLUTION: Algebra 2 word problem: The width of the rectangle is 3 feet less than its length. The perimeter of the rectangle is 110 feet. Find its dimensions.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Algebra 2 word problem: The width of the rectangle is 3 feet less than its length. The perimeter of the rectangle is 110 feet. Find its dimensions.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 992352: Algebra 2 word problem:
The width of the rectangle is 3 feet less than its length. The perimeter of the rectangle is 110 feet. Find its dimensions.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The width of the rectangle is 3 feet less than its length. The perimeter of the rectangle is 110 feet. Find its dimensions.
---
length:: x
width::: x-3
----
P = 2(length + width)
110 = 2(x + x-3)
55 = 2x-3
2x = 58
x = 29 (width)
x-3 = 26 (length)
-----------
Cheers,
Stan H.
----------