SOLUTION: A 336 in. long pipe is cut into three pieces such that the second piece is seventeen in. more than the first piece, and the third piece is twelve in. more than nine times the secon

Algebra ->  Percentages: Solvers, Trainers, Word Problems and pie charts -> SOLUTION: A 336 in. long pipe is cut into three pieces such that the second piece is seventeen in. more than the first piece, and the third piece is twelve in. more than nine times the secon      Log On


   

Question 992325: A 336 in. long pipe is cut into three pieces such that the second piece is seventeen in. more than the first piece, and the third piece is twelve in. more than nine times the second piece.
A) Letting x be the length of the first piece, write an equation that equates the given total length of the board to the sum of the lengths of the three pieces as described in the problem. Make sure your equation models the situation exactly, i.e. do not write a simplified version of the equation.
+ + = 336
1st piece 2nd piece 3rd piece

B) Simplify the left side of your equation:
= 336
C) Solve your equation to find lengths of each of the three pieces: The first piece measures in, the second piece measures in, and the third piece measures in.
Answer by solver91311(24713) About Me  (Show Source):
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Let represent the measure of the second piece. Then represents the measure of the first piece, and is the measure of the third piece. Add 'em up and set them equal to 336.

John

My calculator said it, I believe it, that settles it