Question 992314: sofia is 3 years older than Eunice.In 5 years, Sofia will be twice as old as Eunice will then be. Find their present ages
Found 2 solutions by Timnewman, MathTherapy:
Answer by Timnewman(323)   (Show Source):
You can put this solution on YOUR website! let Eunice age be"x"
Sofia's age=x+3
In 5yrs time,
Eunice;s age=x+5,
Sofia's age=x+8
But sofia will be twice as old,
Then,
x+8=2(x+5)
x+8=2x+10
2x-x=8-10
x=-2
But age cannot be nagative,
Therefore Eunice age is 2yrs,
Sofia's age 5yrs.
FOR MORE UNDERSTANDING,
CLICK HERE:
http//www.algebra.com/cgi-bin/jump-to-question.mpl?question=991063
OR SEE
http//www.algebra.com/cgi-bin/jump-to-question.mpl?question=990905
HOPE THIS HELPS?
Answer by MathTherapy(10553)  (Show Source):
You can put this solution on YOUR website!
sofia is 3 years older than Eunice.In 5 years, Sofia will be twice as old as Eunice will then be. Find their present ages
 based on what you wrote!
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