1. Graph the line , using a solid line because the original equality is inclusive of equality and points on this boundary line are therefore included in the solution set of the inequality.
2. Choose a point on the plane that is NOT on the boundary line. Since the line described in step 1 does not pass through the origin, the point (0,0) is a very good (read "Low impact arithmetic") choice for this point.
3. Substitute the coordinates of the point chosen in step 2 for and in the original inequality. If the result is a true statement, then shade in the half-plane on the side of the line that CONTAINS the chosen point. Otherwise, shade in the other side of the line.
John
My calculator said it, I believe it, that settles it
