SOLUTION: Find all imaginary solutions to each equation. Use the method of your choice. s^2 - 4s +1 =0 I ended up with: s= -1 / (s-4) but my book says I need to get it to be 2 +- sqr

Algebra ->  Equations -> SOLUTION: Find all imaginary solutions to each equation. Use the method of your choice. s^2 - 4s +1 =0 I ended up with: s= -1 / (s-4) but my book says I need to get it to be 2 +- sqr      Log On


   

Question 992231: Find all imaginary solutions to each equation. Use the method of your choice.
s^2 - 4s +1 =0
I ended up with:
s= -1 / (s-4)
but my book says I need to get it to be 2 +- sqrt(3)
Help would be greatly appreciated
Thank you!
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

s%5E2+-+4s+%2B1+=0....use quadratic formula

s+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
s+=+%28-%28-4%29+%2B-+sqrt%28+%28-4%29%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29+
s+=+%284+%2B-+sqrt%28+16-4+%29%29%2F2+
s+=+%284+%2B-+sqrt%28+12+%29%29%2F2+
s+=+%284+%2B-+sqrt%28+4%2A3+%29%29%2F2+
s+=+%284+%2B-+2sqrt%28+3+%29%29%2F2+
s+=+%28cross%284%292+%2B-+cross%282%29sqrt%28+3+%29%29%2Fcross%282%29+
s+=+%282+%2B-+sqrt%28+3+%29%29+
solutions:
s+=+2+%2B+sqrt%28+3+%29+
s+=+2+-+sqrt%28+3+%29+