SOLUTION: x/ x + 2 > 5 word form: X over x + 2 is less than 5? How do i write the answer in interval notation? I do not understand the process to solve this problem.

Algebra ->  Inequalities -> SOLUTION: x/ x + 2 > 5 word form: X over x + 2 is less than 5? How do i write the answer in interval notation? I do not understand the process to solve this problem.      Log On


   

Question 992215: x/
x + 2 > 5

word form: X over x + 2 is less than 5?
How do i write the answer in interval notation?
I do not understand the process to solve this problem.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
x%2F%28x+%2B+2%29%3C5
recall, denominator cannot be equal to zero; so,
if
x+%2B+2%3E0 =>x%3E-2
now find x that makes x%2F%28x+%2B+2%29=5
x%3C5%28x+%2B+2%29
x=5x+%2B+10
-10=5x+-x
-10=4x
-10%2F4=x
x=-5%2F2=> x must be lees than -5%2F2
so, your solution is: x%3E-2 and x%3C-5%2F2
in interval notation:
(-2, infinity)
(-infinity, -5%2F2)

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+x%2F%28x+%2B+2%29%2C+5%29+