SOLUTION: A student who can afford to spend up to $2,200 sees the ad shown in the illustration. If she buys a computer, how many games can she buy? Image is in the following link.. https

Algebra ->  Inequalities -> SOLUTION: A student who can afford to spend up to $2,200 sees the ad shown in the illustration. If she buys a computer, how many games can she buy? Image is in the following link.. https      Log On


   

Question 992177: A student who can afford to spend up to $2,200 sees the ad shown in the illustration. If she buys a computer, how many games can she buy?
Image is in the following link..
https://www.webassign.net/gfcolalg/1-7-82.gif
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let
x = number of games bought
y = total cost (computer + games)

The laptop costs $1,695.95. This is the fixed cost. It does not change based on the number of games bought.

The variable cost is the cost associated with the games bought. If you buy x games, then it will cost you x*19.95 = 19.95x dollars.

The total cost is therefore
y = 19.95x + 1695.95

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We are given "A student who can afford to spend up to $2,200"

So 2200 dollars is the max amount allowed to be spent. Plug in y = 2200 and solve for x


y = 19.95x + 1695.95


2200 = 19.95x + 1695.95 ... replace y with 2200


2200 - 1695.95 = 19.95x + 1695.95 - 1695.95 ... Subtract 1695.95 from both sides.


504.05 = 19.95x


504.05/19.95 = 19.95x/19.95 ... Divide both sides by 19.95 to isolate x.


25.265664160401 = x


x = 25.265664160401


x = 25 ... round down to the nearest whole number


So this student can buy at most 25 games. If she bought 26 games, then she'd go over budget (notice how 19.95*26 + 1695.95 = $2,214.65 is larger than $2,200)