SOLUTION: find the dimensions of a rectangle with a perimeter of 64 meters if its length is 4 meters less than twice the width.
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Question 992123: find the dimensions of a rectangle with a perimeter of 64 meters if its length is 4 meters less than twice the width. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
W=width; L=length=2W-4m
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P=2(L+W)
64m=2(2W-4m+W)
32m=3W-4m
36m=3W
12m=W . ANSWER 1: The width is 12 meters.
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L=2W-4m=2(12m)-4m=24m-4m=20m
ANSWER 2: The length is 20 meters.
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CHECK:
P=2(L+W)
64m=2(20m+12m)
64m=2(32m)
64m=64m
