SOLUTION: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 45% and the third contains 85%. He wants to use all three solutions to
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Question 991928: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 45% and the third contains 85%. He wants to use all three solutions to obtain a mixture of 160 liters containing 40% acid, using 3 times as much of the 85% solution as the 45% solution. How many liters of each solution should be used?
The chemist should use
liters of 25% solution,
liters of 45% solution, and
liters of 85% solution. Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39618) (Show Source):
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A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 45% and the third contains 85%. He wants to use all three solutions to obtain a mixture of 160 liters containing 40% acid, using 3 times as much of the 85% solution as the 45% solution. How many liters of each solution should be used?
The chemist should use
liters of 25% solution,
liters of 45% solution, and
liters of 85% solution.
Amount of 25% acid to use: L
Amount of 45% acid to use: L
Amount of 85% acid to use: L
This makes sense since the resulting mixture is to contain 40% acid, so the great majority of the mixture needs to consist of 25% acid