Question 991736: Find all solutions of csc x = -2, where 0 ≤ x ≤ 2π. Can you explain step by step how you got the answer.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find all solutions of csc x = -2, where 0 ≤ x ≤ 2π.
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If csc(x) = -2, sin(x) = 1/csc(x) = -1/2
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If sin = -1/2, the reference angle is pi/6
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Since sin is negative in QIII and QIV
x = pi+(pi/6) = (7/6)pi
or x = (2pi)-(pi/6) = (11/6)pi
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Cheers,
Stan H.
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