Question 991579: The smaller of two consecutive integers is eight less than twice the greater. Find the smaller of the two numbers Answer by macston(5194) (Show Source):
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S=smaller integer=x; L=larger integer=x+1
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S+8=2L
x+8=2(x+1)
x+8=2x+2
6=x
ANSWER: The smaller integer is 6.
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CHECK:
L=x+1=6+1=7
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S+8=2L
S+8=2L
6+8=2(7)
14=14