Question 991535: Ron has 20 coins with a total value of $1.50. The coins are nickels and dimes. How many of each coin does he have? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
N=number of nickels; D=number of dimes
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N+D=20
N=20-D
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$0.05N+$0.10D=$1.50
$0.05(20-D)+$0.10D=$1.50
$1.00-$0.05D+$0.10D=$1.50
$0.05D=$0.50
D=10
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N=20-D=20-10=10
ANSWER: He has 10 of each coin.
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CHECK:
$0.05N+$0.10D=$1.50
$0.05(10)+$0.10(10)=$1.50
$0.50+$1.00=$1.50
$1.50=$1.50