SOLUTION: Find three consecutive odd numbers such that four times the first number decreased by 28 is equal to the sum of the last two numbers.

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Question 991532: Find three consecutive odd numbers such that four times the first number decreased by 28 is equal to the sum of the last two numbers.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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x, x+2, x+4 are the three integers
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4x-28=(x+2)+(x+4)
4x-28=2x+6
2x=34
x=17 ANSWER 1: The first number is 17.
x+2=17+2=19 ANSWER 2: The second number is 19.
x+4=17+4=21 ANSWER 3: The third number is 21.
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CHECK:
4(17)-28=19+21
68-28=40
40=40