SOLUTION: How many pounds of 80 cent nuts and how many pounds of 50 cent nuts must a dealer use to produce a mixture of 90 pounds to sell at 75 cents per pound?

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Question 991363: How many pounds of 80 cent nuts and how many pounds of 50 cent nuts must a dealer use to produce a mixture of 90 pounds to sell at 75 cents per pound?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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E=pounds of 80 cent nuts; F=pounds of 50 cent nuts
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E+F=90 pounds
F=90 pounds-E
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0.50F+0.80E=0.75(90 pounds)
0.50(90lbs-E)+0.80E=67.5lbs
45lbs-0.50E+0.80E=67.5lbs
0.30E=22.5lbs
E=75lbs
ANSWER 1: he should use 75 pounds of $0.80 per pound nuts.
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F=90lbs-E=90lbs-75lbs=15lbs
ANSWER 2: He should use 15 pounds of $0.50 per pound nuts.
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CHECK:
0.50F+0.80E=0.75(90 pounds)
0.50(15lbs)+0.80(75lbs)=67.5lbs
7.5lbs+60lbs=67.5lbs
67.5lbs=67.5lbs