SOLUTION: A 173 inch long pipe is cut into three pieces such that the second piece is six inches more than the first piece, and the third piece is nineteen inches more than eight times the s

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A 173 inch long pipe is cut into three pieces such that the second piece is six inches more than the first piece, and the third piece is nineteen inches more than eight times the s      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 991250: A 173 inch long pipe is cut into three pieces such that the second piece is six inches more than the first piece, and the third piece is nineteen inches more than eight times the second piece.
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Make first piece = 'x'
Second piece = x + 6
Third piece = 19 + 8(x + 6)
Add all pieces together:
x + x + 6 + 19 + 8(x + 6)
x + x + 6 + 19 + 8x + 48
= 10x + 73
Now the pipes length is 173 inches.
So:- 10x + 73 = 173
10x = 100
x = 10
So,
First piece = 10 inches
Second piece = 16 inches
Third piece = 147 inches
Hope this helps :-)