SOLUTION: You have a set of 3 integers, each one being 3 higher than the previous one. The sum of the second and third integers is 1 more than 4 times the first integer.
Algebra ->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: You have a set of 3 integers, each one being 3 higher than the previous one. The sum of the second and third integers is 1 more than 4 times the first integer.
Log On
Question 991206: You have a set of 3 integers, each one being 3 higher than the previous one. The sum of the second and third integers is 1 more than 4 times the first integer. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! You have a set of 3 integers, each one being 3 higher than the previous one. The sum of the second and third integers is 1 more than 4 times the first integer.
-----
1st:: x
2nd: x + 3
3rd: x + 6
-----
Equation:
x+3 + x+6 = 4x+1
----
2x+9 = 4x+1
2x = 8
x = 4 (1st)
x+3 = 7 (2nd)
x+6 = 10 (3rd)
-----------
Cheers,
Stan H.
----------
(