SOLUTION: juanita is twice as old as vanessa, if five years were subtracted from vanessas age, and two years added to juanitas, juanita will be five times as old as vanessa. How old are the

Algebra ->  Human-and-algebraic-language -> SOLUTION: juanita is twice as old as vanessa, if five years were subtracted from vanessas age, and two years added to juanitas, juanita will be five times as old as vanessa. How old are the       Log On


   



Question 991183: juanita is twice as old as vanessa, if five years were subtracted from vanessas age, and two years added to juanitas, juanita will be five times as old as vanessa. How old are the girls now?
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
juanita is twice as old as vanessa,
J = 2V
if five years were subtracted from vanessas age,
and two years added to juanitas, juanita will
be five times as old as vanessa.
J + 2 = 5(V - 5)
Replace J with 2V from top equation.
2V + 2 = 5(V - 5)
2V + 2 = 5V - 25
Collect like terms.
2V - 5V = -25 - 2
-3V = -27
V = 9
Vanessa is 9 years old
Juanita is 18 years old.
Hope this helps :-)