SOLUTION: How do you do this exercise: logB = 3(log x -1) -2 (1 - log y)

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Question 991094: How do you do this exercise:
logB = 3(log x -1) -2 (1 - log y)
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Is this it:
+log%28+B+%29+=+3%2A%28+log%28+x+%29+-+1+%29+-+2%2A%28+l-+log%28y%29+%29+
If so,
+log%28B%29+-+3%2Alog%28x%29+-+3+-+2+%2B+log%28y%29+
+log%28B%29+%2B+log%28y%29+-+log%28+x%5E3+%29+-+5+
+log%28+%28%28B%2Ay%29%2Fx%5E3%29%29+-+5+
Hope I got it

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
logB = 3(log x -1) -2 (1 - log y)
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I'll assume you want to solve for "y":
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2(1-log(y)) = 3(log(x)-1) - log(B)
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2 - 2log(y) = 3log(x) - 3 - log(B)
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-2log(y) = log(x^3/B) - 5
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log(y) = (5/2)-log[sqrt(x^3/B)]
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log(y) = (5/2) - log[x^(3/2)/B^(1/2)]
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y = 10^[(5/2) - log[x^(3/2)/B^(1/2)]]
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Cheers,
Stan H.