SOLUTION: Consider the recursive rule u(n) =0.85u(n-1) +147 [This is u sub n and 0.85 u sub n-1] the long run value of any shifted geometeric sequence that is generated by this recursi

Algebra ->  Sequences-and-series -> SOLUTION: Consider the recursive rule u(n) =0.85u(n-1) +147 [This is u sub n and 0.85 u sub n-1] the long run value of any shifted geometeric sequence that is generated by this recursi      Log On


   

Question 990873: Consider the recursive rule
u(n) =0.85u(n-1) +147 [This is u sub n and 0.85 u sub n-1]
the long run value of any shifted geometeric sequence that is generated by this recursive rule is
147/.15 = 980
Sketch a graph sequence that is generated by this recursive rule and has a starting value below the long run value.. <— please help
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
It is hard to figure out what the instructor expected without knowing him/her.
I guess that all that is expected is a graph were you plot some values and draw a smooth continuous line connecting them.
Graphing the values of b%5Bn%5D on the y-axis vs the value of n on the x-axis,
the sequence would be represented as separate points.
You can start with an arbitrary value for b%5B1%5D ,
and tabulate the values of the next few sequence terms.
For example

Then you could plot all or some of those, and sketch what it would look for other values of n .

Maybe they just expect that you would guess that it is like an upside-down exponential decay,
and draw something like