SOLUTION: Joseph mixed a certain amount of 10% isopropyl mixture with 60 gallons of a 20% isopropyl solution, and the resulting mixture is 16% isopropyl. How much of the 10% isopropyl did h
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Question 99077: Joseph mixed a certain amount of 10% isopropyl mixture with 60 gallons of a 20% isopropyl solution, and the resulting mixture is 16% isopropyl. How much of the 10% isopropyl did he add? Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! Let x=amount of 10% mixture that he used
(1) Now the amount of pure isopropyl in this mixture is 0.10x
(2) Amount of pure isopropyl in the 20% mixture is 0.20(60)
(3) Amount of pure isopropyl in the final mixture is 0.16(60+x)
Now we know that 1+2=3. So our equation to solve is:
0.10x+0.20*60=0.16(60+x) get rid of parens
0.10x+12=9.6+0.16x subtract 9.6 and also 0.10x from both sides
0.10x-0.10x+12-9.6=9.6-9.6+0.16x-0.10x collect like terms
2.4=0.06x divide both sides by 0.06
x=40 gal--------------------amount of 10% solution used
CK
0.10*40+0.20*60=0.16*100
4+12=16
16=16
Hope this helps---ptaylor
