SOLUTION: A Restaurant wants to purchase 40 pounds of party mix for a total of $100. They will mix nuts that cost $3 a pound, with pretzels that cost $2 a pound. How many pounds of each type

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A Restaurant wants to purchase 40 pounds of party mix for a total of $100. They will mix nuts that cost $3 a pound, with pretzels that cost $2 a pound. How many pounds of each type      Log On


   



Question 990751: A Restaurant wants to purchase 40 pounds of party mix for a total of $100. They will mix nuts that cost $3 a pound, with pretzels that cost $2 a pound. How many pounds of each type of mix should they use?
Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Cost of the mix equals cost of the materials to buy.

n, how many pounds nuts;
p, how many pounds pretzels;
system%28100=3%2An%2B2%2Ap%2Cn%2Bp=40%29

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = pounds of nuts needed
Let +b+ = pounds of pretzels needed
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(1) +a+%2B+b+=+40+
(2) +3a+%2B+2b+=+100+
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Multiply both sides of (1) by +2+ and
subtract (1) from (2)
(2) +3a+%2B+2b+=+100+
(1) +-2a+-+2b+=+-80+
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+a+=+20+
and
(1) +a+%2B+b+=+40+
(1) +20+%2B+b+=+40+
(1) +b+=+20+
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They used 20 pounds of nuts and
20 pounds of pretzels
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check:
(2) +3a+%2B+2b+=+100+
(2) +3%2A20+%2B+2%2A20+=+100+
(2) +60+%2B+40+=+100+