SOLUTION: Distance–Rate–Time. A long-distance delivery service sends out a truck with a package at 7 A.M. At 7:30 A.M., the manager realizes there was another package going to the same locat

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Question 990740: Distance–Rate–Time. A long-distance delivery service sends out a truck with a package at 7 A.M. At 7:30 A.M., the manager realizes there was another package going to the same location. He sends out a car to catch the truck. If the truck travels at an average speed of 20 miles per hour and the car travels at 80 miles per hour, how long will it take the car to catch the truck?
Round your answer to the nearest minute.

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
The truck travels for more time and travels slower than the car. Car and truck meet when they each go the same distance from departure. Half hour difference between 7AM and 7:30AM.

VEHICLE     SPEED     TIME     DISTANCE
Truck       20        t+1/2     d
Car         80         t        d


RT=D relates rate, time, distance; for uniform travel rates.

system%2820%28t%2B1%2F2%29=d%2C80t=d%29

highlight%2820%28t%2B1%2F2%29=80t%29
Solve for t.