SOLUTION: The number of ways in which the number 27720 can be split into the product of two factors that are coprimes is

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Question 990562: The number of ways in which the number 27720 can be split into the product of two factors that are coprimes is
Answer by ikleyn(52830) About Me  (Show Source):
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27720 = 8*9*5*7*11

is the presentation of the number  27720  as the product of five co-prime numbers  8, 9, 5, 7, and 11.

So,  we have basically  5  co-prime numbers,  and the question is:  in how many ways we can collect some of them into the first factor?  (Then the rest of them will
automatically go into the second factor).  The order of co-primes in the first factor does not make a difference.  (Same as the order in the second factor does not).

It is the same as to ask:  how many sub-sets is there in the set of  5  object?

The answer is:  2%5E5.

Indeed,  the empty sub-set corresponds to the value  1  of the first factor.

The sub-sets consisting of  1  elements,  give the values of 8, 9, 5, 7, and 11  for the first factor.

The sub-sets consisting of 2 elements give the factors 8*9, 8*5, 8*7, . . . , 7*11.

The sub-sets . . . . and so on.

Thus the number of ways in which we can construct the first factor is  2%5E5.
But since we do not make the difference between the first and the second factors,  we need to divide this number by  2.

So,  the answer is:  The number of ways in which the number  27720  can be split into the product of two co-prime factors is  2%5E4.