Question 990362: Find three consecutive even integers such that the sum of 6 times the first number and two times the third number equals 200 Answer by macston(5194) (Show Source):
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F=first integer; S=second integer=F+2; T=third integer=F+4
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6F+2T=200
6F+2(F+4)=200
6F+2F+8=200
8F=192
F=24
S=F+2=24+2=26
T=F+4=24+4=28
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ANSWER: The three numbers are 24,26, and 28.