SOLUTION: Why is it that when you have a number (context of money) for example £64.83 and swap the pounds and pence, eg. £83.64 then add those together....£148.47 then swap the tens and ones

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Question 990357: Why is it that when you have a number (context of money) for example £64.83 and swap the pounds and pence, eg. £83.64 then add those together....£148.47 then swap the tens and ones with tenths and hundredths again, eg. £147.48 and add THOSE numbers.....£295.95 the tens and ones number is the same as the tenths and hundredths number?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
It is not always so. It works half of the time. It all depends on the digits.

If you start with 67.89, it does not work.
The first swap gives you 89.67;
the first sum is 157.56, which reversed is 156.57,
and the second sum is 314.13.

If you start with 34.25, it does not work either.
The first swap gives you 25.34;
the first sum is 59.59, which reversed is also 59.59,
and the second sum is 119.18.

It worked for your example.

If you start with 14.26, it also works.
The first swap gives you 26.14;
the first sum is 40.40, which reversed is also 40.40,
and the second sum is 80.80.

p= number of whole pounds, with p%3C=99
c= number of cents, with c%3C=99
The amount value, in cents, is 100p%2Bc .
Swapping the numbers of pounds and cents, we have a value of 100c%2Bp .
Adding both values, we get 100p%2Bc%2B100c%2Bp=100%28p%2Bc%29%2B%28p%2Bc%29 .
From then on, it all depends on the value of p%2Bc .

If p%2Bc%3C=49%3C99, it works.
For the first sum,
p%2Bc is the two-digit number that makes up the tens and ones, and
p%2Bc is also the two-digit number that makes up the cents (the tenths and hundredths).
Then, swapping the tens and ones with tenths and hundredths gives you the same number.
Adding swapped and unswapped, you get
100%28p%2Bc%29%2B%28p%2Bc%29%2B100%28p%2Bc%29%2B%28p%2Bc%29=100%282p%2B2c%29%2B%282p%2B2c%29 .
Since p%2Bc%3C=49 , 2p%2B2c%3C=98 ,
2p%2B2c is a two-digit number that makes up the tens and ones, and
2p%2B2c is also the two-digit number that makes up the cents (the tenths and hundredths).

If 50%3C=p%2Bc%3C=99, as in the case of 34.25, it does not work.
For the first sum,
p%2Bc is a two-digit number that makes up the tens and ones, and
p%2Bc is also the two-digit number that makes up the cents (the tenths and hundredths).
Then, swapping the tens and ones with tenths and hundredths gives you the same number.
Adding swapped and unswapped, you get
100%28p%2Bc%29%2B%28p%2Bc%29%2B100%28p%2Bc%29%2B%28p%2Bc%29=100%282p%2B2c%29%2B%282p%2B2c%29 .
Since 50%3C=p%2Bc%3C=99 , 100%3C=2p%2B2c%3C=198 ,
2p%2B2c=100%2B%282p%2B2c-100%29 is a three-digit number,
but %282p%2B2c-100%29%3C=98 and is a two-digit number.
The second sum is
.
%282p%2B2c-100%29 is a two-digit number that represents the cents,
cents represents the 1 in the hundreds place.

If 100%3C=p%2Bc%3C=149, as in the case of 83.64, it works.
The first sum is
, where
p%2Bc-100 is the two-digit number that makes up the cents (the tenths and hundredths),
p%2Bc-100%2B1 is the two-digit number that makes up the tens and ones,
and the 10000 cents represents the 1 in the hundreds place.
Swapping the tens and ones with tenths and hundredths yields
10000%2B100%28p%2Bc-100%29%2B%28p%2Bc-100%2B1%29 cents.
Adding swapped and unswapped we get (in cents)
.
Since 100%3C=p%2Bc%3C=149 , 200%3C=2p%2B2c%3C=298 ,
and 1%3C=2p%2B2c-200%2B1%3C=99 is the two digit number that
makes up the tens and ones, and also makes up the tenths and hundredths.

If 150%3C=p%2Bc%3C=198 , as in the case of 67.89, it does not work.
The first sum is
10000%2B100%28p%2Bc-100%2B1%29%2B%28p%2Bc-100%29 , where
p%2Bc-100 is the two-digit number that makes up the cents (the tenths and hundredths),
p%2Bc-100%2B1 is the two-digit number that makes up the tens and ones,
and the 10000 cents represents the 1 in the hundreds place.
Swapping the tens and ones with tenths and hundredths yields
10000%2B100%28p%2Bc-100%29%2B%28p%2Bc-100%2B1%29 cents.
Adding swapped and unswapped we get (in cents)
20000%2B100%282p%2B2c-200%2B1%29%2B%282p%2B2c-200%2B1%29 .
However, since 150%3C=p%2Bc%3C=198,
300%3C=2p%2B2c%3C=396 , and 101%3C=2p%2B2c-200%2B1%3C=197 ,
so the second sum is

=30000%2B100%282p%2B2c-300%2B2%29%2B%282p%2B2c-300%2B1%29 , where
%282p%2B2c-300%2B1%29 is the two-digit number that makes up the cents (the tenths and hundredths),
%282p%2B2c-300%2B1%29 is the two-digit number that makes up the tens and ones,
and the 30000 cents represents the 3 in the hundreds place.