SOLUTION: The sum of 3 consecutive odd integers times One times the integer, twice times the second times 3 times the 3rd is equal to 70

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Question 990350: The sum of 3 consecutive odd integers times One times the integer, twice times the second times 3 times the 3rd is equal to 70
Answer by Alan3354(69443) About Me  (Show Source):
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The sum of 3 consecutive odd integers times One times the integer, twice times the second times 3 times the 3rd is equal to 70
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(n-2) + 2n + 3(n+2) = 70
6n + 4 = 70
n = 11