SOLUTION: A license consists of 1 letter followed by 1 digit followed by 1 digit followed by 3 letters. Assuming no resrictions, which expression shows how many licenses can be issued? A

Algebra ->  Permutations -> SOLUTION: A license consists of 1 letter followed by 1 digit followed by 1 digit followed by 3 letters. Assuming no resrictions, which expression shows how many licenses can be issued? A      Log On


   



Question 99010: A license consists of 1 letter followed by 1 digit followed by 1 digit followed by 3 letters. Assuming no resrictions, which expression shows how many licenses can be issued?
A- (26)(10)(25)(24)(23)
B- (26)(10)(25)(25)(25)
C- (26)(10)(26)(25)(24)
D- (26)(10)(26)(26)(26)
Thanks in advanced for anyone that helps.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A license consists of 1 letter followed by 1 digit followed by 1 digit followed by 3 letters. Assuming no resrictions, which expression shows how many licenses can be issued?
A- (26)(10)(25)(24)(23)
B- (26)(10)(25)(25)(25)
C- (26)(10)(26)(25)(24)
D- (26)(10)(26)(26)(26)
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Licence = letter,digit,digit,letter,letter,letter
= 26,10,10,26,26,26
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None of the above unless you posted the problem incorrectly.
You need "10" twice because you posted digit,digit.
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Cheers,
Stan H.