SOLUTION: Gilbert discovered $2.75 worth of nickels and dimes. He had 35 coins. How many coins of each did he have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Gilbert discovered $2.75 worth of nickels and dimes. He had 35 coins. How many coins of each did he have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 990048: Gilbert discovered $2.75 worth of nickels and dimes. He had 35 coins. How many coins of each did he have?
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
d = number of dimes

n + d = 35
5n + 10d = 275

Multiply the first equation by 10.

10n + 10d = 350
-(5n + 10d = 275)
---------------------
5n = 75
n = 15

Gilbert has 15 nickels and 20 dimes.