SOLUTION: Two scout troops are camping. One troop has 40 members and the other 48 members. The scout masters want to divide them into groups. How can the scouts of the two troops be grou

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: Two scout troops are camping. One troop has 40 members and the other 48 members. The scout masters want to divide them into groups. How can the scouts of the two troops be grou      Log On


   

Question 990013: Two scout troops are camping. One troop has 40 members and the other 48 members. The scout masters want to divide them into groups. How can the scouts of the two troops be grouped so that each group has the biggest number possible of scouts and each group has the same number of scouts with no scouts left out?
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
We are finding the GCD (greatest common divisor) of 40 and 48.

40 = 2^3 * 5
48 = 2^4 *3

GCD(40, 48) = 2^3 = 8